Umbraco Forms submitted record values on success page

Questions
,
4

Hi @kevinm!

You should be able to do something along these lines to get the value…

@using Umbraco.Forms.Core.Models
@using Umbraco.Forms.Core.Persistence.Dtos
@using Umbraco.Forms.Core.Data.Storage
@using Umbraco.Forms.Core.Services
@inject IFormService _formService
@inject IRecordStorage _recordStorage
@inherits UmbracoViewPage
@{
	Guid formId;
	Form? form;
	Guid recordId;
	Record? record;

	if (TempData["UmbracoFormSubmitted"] != null)
	{
		Guid.TryParse(TempData["UmbracoFormSubmitted"]?.ToString(), out formId);

		form = _formService.Get(formId);

		if (form != null && TempData["Forms_Current_Record_id"] != null)
		{
			Guid.TryParse(TempData["Forms_Current_Record_id"]?.ToString(), out recordId);

			record = _recordStorage.GetRecordByUniqueId(recordId, form);
		}
	}
}

There may be better ways of null checking than this, but conceptually this is how you should be able to get these records on the success page.